The quotient Rule
d(u/v) /dx = (vdu/dx - udv/dx)/ v2
For example:
f(x) = y = cos(x)/sin(x) or y = cot (x)
Let u = cos(x) v = sin(x)
Then calculate
u' = -sin(x) v' = cos(x)
then substitute
y' = (vdu/dx - udv/dx)/ v2
= (sin(x)(-sin(x)) - cos(x)(cos(x)))/ sin2 (x)
= -(sin2(x) + cos2 (x))/ sin2 (x)
= -1/ sin2 (x)
y'(.5) = -4.35069
Check the result with nDeriv(tan-1(x),x,.5)
nDeriv = -4.35070
if you can't remember what gets substracted from what.
try something easy like
d(x/1)/dx
Let u = x and v = 1 then
du/dx = 1 and dv/dx = 0
d(x/1)/dx = ((1)(1) - x (0))/ (1)2
= 1
This is true, the derivative of x is 1
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